Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Review - Exercises - Page 70: 24



Work Step by Step

$f(x)=y=\frac{x+1}{2x+1}$ $2xy+y=x+1$ $x(2y-1)=1-y$ $f^{-1}(y)=\frac{1-y}{2y-1}$ $\therefore f^{-1}(x)=\frac{1-x}{2x-1}$
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