Answer
$\frac{11}{13}$+ $\frac{10}{13}$i
Work Step by Step
1. $\frac{1+4i}{3+2i}$ $\times$ $\frac{(3-2i)}{(3-2i)}$
2. $\frac{3-2i+12i-(8\times-1)}{9-6i+6i-(4\times-1)}$ ,$ i^{2}$ equals -1
3. $\frac{11+10i}{13}$
4. $\frac{11}{13}$ + $\frac{10}{13}$i
