Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX H - Complex Numbers - H Exercises: 7

Answer

$\frac{11}{13}$+ $\frac{10}{13}$i

Work Step by Step

1. $\frac{1+4i}{3+2i}$ $\times$ $\frac{(3-2i)}{(3-2i)}$ 2. $\frac{3-2i+12i-(8\times-1)}{9-6i+6i-(4\times-1)}$ ,$ i^{2}$ equals -1 3. $\frac{11+10i}{13}$ 4. $\frac{11}{13}$ + $\frac{10}{13}$i
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