Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX H - Complex Numbers - H Exercises: 16

Answer

Conjugate: $-1-2\sqrt(2)i$ Modulus: $3$

Work Step by Step

Conjugate: $-1+2\sqrt(2)i = -1-2\sqrt(2)i$ Modulus: $\sqrt((-1)^2+(-2\sqrt(2)^2)=\sqrt(1+8)=\sqrt(9)=3$
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