Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX E - Sigma Notation - E Exercises: 17

Answer

$\displaystyle \sum_{i=0}^{5}2^{i}$

Work Step by Step

We contract the sum into sigma notation by noting that it follows the pattern of a sum of powers of 2 (e.g. $2^i$), starting with $1$ (e.g. $i=0$), and ending with $32$ (e.g. $i=5$). $1+2+4+8+16+32=\displaystyle \sum_{i=0}^{5}2^{i}$
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