Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX E - Sigma Notation - E Exercises - Page A 38: 16

Answer

$\sum_{i=1}^{n}(2i-1)$

Work Step by Step

We contract the sum into sigma notation by noting that it follows the pattern of a sum of odd integers (e.g. $2i-1$), starting with $1$ (e.g. $i=1$), and ending with $2n-1$ (e.g. $i=n$). $1+3+5+7+\displaystyle \cdots+(2n-1)=\sum_{i=1}^{n}(2i-1)$
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