Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 9 - Power Series - Review Exercises - Page 706: 60

Answer

$-1.175$

Work Step by Step

The Taylor approximation for a function $\sinh(x)$ centred at $a=0$ can be written as: $p(x)=x+\dfrac{x^3}{3!}+\dfrac{x^5}{5!}+.........$---- Now, we have: $p(-1)=(-1)+\dfrac{(-1)^3}{3!}+\dfrac{(-1)^5}{5!}+.......=-1.175$ Therefore, $\sinh (-1)=-1.175$
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