Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 9 - Power Series - Review Exercises - Page 705: 3

Answer

$1$

Work Step by Step

The Taylor approximation for degree $n$ centered at point $a$ can be written as: $P_n(x)=f(a)+f'(a)(x-a)+\dfrac{1}{2}f''(a)(x-a)^2+.......+\dfrac{1}{n!}f^n(a)(x-a)^n ~~~~........(1)$---- We have: $f(x)=\cos x^2\implies f(0)=\cos (0)=1$ Further, $f'(x)=-2 x \sin (x^2) \implies f'(0)=0 \\ f''(x)=-2 \sin x^2-4x^2 \cos x^2 \implies f''(0)=0\\ f'''(x)=-8 \cos (2x) \implies f'''(0)=-8$ Now, plug these values in the equation (1) to obtain: $P_2(x)=f(0)+f'(0)x+\dfrac{1}{2!}f''(0)x^2\\=1+0+0\\=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.