Answer
$\{5(-1.01)^n\}$ diverges and oscillates.
Work Step by Step
The general form of a geometric sequence is $a^r$.
For the sequence $\{5(-1.01)^n\}$, we can ignore the $5$ because it's a constant and is not affected by $n$. $|a| \geq 1$, meaning that the sequence diverges. Due to the negative sign in $a$, the sequence also oscillates.
