Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - Review Exercises - Page 595: 96

Answer

$$y = \left(\frac{5}{2} - \frac{1}{2}\cos t\right)^2 $$

Work Step by Step

$$\eqalign{ & \frac{{dy}}{{dt}} = \sqrt y \sin t,\,\,\,\,\,\,y\left( 0 \right) = 4 \cr & {\text{Separate the variables}} \cr & {y^{ - 1/2}}dy = \sin tdt \cr & {\text{Integrating}} \cr & \frac{{{y^{1/2}}}}{{1/2}} = - \cos t + C \cr & 2\sqrt y = - \cos t + C \cr & {\text{Use the initial condition }}\,y\left( 0 \right) = 4 \cr & 2\sqrt 4 = - \cos \left( 0 \right) + C \cr & 4 + 1 = + C \cr & C = 5 \cr & ,{\text{ then}} \cr & 2\sqrt y = - \cos t + 5 \cr & {\text{Solve for }}y \cr & \sqrt y = \frac{5}{2} - \frac{1}{2}\cos t \cr & y = \left(\frac{5}{2} - \frac{1}{2}\cos t\right)^2 \cr} $$
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