Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.4 Trigonometric Substitutions - 7.4 Exercises - Page 539: 76

Answer

$${\sin ^{ - 1}}\left( {x - 2} \right) + C$$

Work Step by Step

$$\eqalign{ & \int {\frac{{dx}}{{\sqrt {\left( {x - 1} \right)\left( {3 - x} \right)} }}} \cr & {\text{Use FOIL}} \cr & {\text{ = }}\int {\frac{{dx}}{{\sqrt {3x - {x^2} - 3 + x} }}} \cr & {\text{ = }}\int {\frac{{dx}}{{\sqrt {4x - {x^2} - 3} }}} \cr & {\text{Completing the square}} \cr & 4x - {x^2} - 3 = 1 - {\left( {x - 2} \right)^2} \cr & {\text{ = }}\int {\frac{{dx}}{{\sqrt {1 - {{\left( {x - 2} \right)}^2}} }}} \cr & {\text{The integrand contains the form }}{a^2} - {u^2} \cr & {\text{Use the change of variable }}x - 2 = a\sin \theta \cr & x - 2 = \sin \theta ,\,\,\,\,\,\,dx = \cos \theta d\theta \cr & {\text{Use the change of variable}} \cr & {\text{ = }}\int {\frac{{\cos \theta d\theta }}{{\cos \theta }}} \cr & = \int {d\theta } \cr & = \theta + C \cr & {\text{Write in terms of }}x \cr & = {\sin ^{ - 1}}\left( {x - 2} \right) + C \cr} $$
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