Answer
$\int ^2 _0 (4x^3)dx = 16 $
Work Step by Step
$\int ^2 _0 (4x^3)dx = (4\frac{x^4}{4})|^2_0 = x^4|^2_0 =2^4 - 0^4 = 16 $
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 5 - Integration - 5.3 Fundamental Theorem of Calculus - 5.3 Exercises - Page 374: 29
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