Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - Review Exercises: 75

Answer

$$\frac{1}{2}sec2x + C$$

Work Step by Step

$$\eqalign{ & \int {\sec 2x\tan 2x} dx \cr & {\text{use the formula for indefinite integrals of trigonometric functions}} \cr & \int {\sec ax} \tan axdx = \frac{1}{a}secax + C \cr & {\text{letting }}a = 2,{\text{ we have}} \cr & = \frac{1}{2}sec2x + C \cr} $$
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