Answer
$$\boxed{{x^2}\cos {x^3}}$$
Work Step by Step
$$\eqalign{
& \text{differentiate} \cr
& = \frac{d}{{dx}}\left( {\frac{1}{3}\sin {x^3} + C} \right) \cr
& = \frac{1}{3}\frac{d}{{dx}}\left( {\sin {x^3}} \right) + \frac{d}{{dx}}\left( C \right) \cr
& {\text{by the chain rule}} \cr
& = \frac{1}{3}\left( {\cos {x^3}} \right)\frac{d}{{dx}}\left( {{x^3}} \right) \cr
& = \frac{1}{3}\left( {\cos {x^3}} \right)\left( {3{x^2}} \right) \cr
& {\text{simplify}} \cr
& = {x^2}\cos {x^3} \cr} $$