Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises: 105

Answer

$${\csc ^2}\theta + 2{\theta ^2} - 3\theta $$

Work Step by Step

$$\eqalign{ & \int {\left( {{{\csc }^2}\theta + 2{\theta ^2} - 3\theta } \right)d\theta } \cr & {\text{split the integrand}} \cr & = \int {{{\csc }^2}\theta d\theta } + \int {2{\theta ^2}d\theta } - \int {3\theta d\theta } \cr & {\text{integrate}} \cr & = - \cot \theta + \frac{2}{3}{\theta ^3} - \frac{3}{2}{\theta ^2} + C \cr & {\text{check by differentiation}} \cr & {\text{ = }}\frac{d}{{d\theta }}\left( { - \cot \theta + \frac{2}{3}{\theta ^3} - \frac{3}{2}{\theta ^2} + C} \right) \cr & {\text{ = }}\frac{d}{{d\theta }}\left( { - \cot \theta } \right) + \frac{d}{{d\theta }}\left( {\frac{2}{3}{\theta ^3}} \right) + \frac{d}{{d\theta }}\left( { - \frac{3}{2}{\theta ^2}} \right) + \frac{d}{{d\theta }}\left( C \right) \cr & {\text{ = }} - \left( { - {{\csc }^2}\theta } \right) + \frac{2}{3}\left( {3{\theta ^2}} \right) - \frac{3}{2}\left( {2\theta } \right) + 0 \cr & {\text{simplify}} \cr & {\text{ = }}{\csc ^2}\theta + 2{\theta ^2} - 3\theta \cr} $$
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