Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 256: 22

Answer

$f$ is increasing on $(0,1) \cup (2,\infty)$, $f$ is decreasing on $(-\infty,0) \cup (1,2)$.
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Work Step by Step

$f'(x) = 4x^3 − 12x^2 + 8x = 4x(x^2 − 3x + 2) = 4x(x − 2)(x − 1)$, which is $0$ when $x$ is $0$, $1$, or $2$. On $(−∞, 0)$ , $f' < 0$ so $f$ is decreasing. On $(0, 1)$, $f' > 0$ so $f$ is increasing. On $(1, 2)$, $f' < 0$ so $f$ is decreasing, and on $(2,∞)$, $f' > 0$ so $f$ is increasing.
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