Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 256: 16

Answer

See the graph.
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Work Step by Step

Since $f'(-3)=0$ and sign of $f'(x)$ is changing from positive to negative around $-3$, so $f'(x)$ have local maxima at $x=-3$ , also $f'(1)=0$ and sign of $f'(x)$ ia changing from negative to positive , so $f'(x)$ have local minima at $x=1$.
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