## Calculus: Early Transcendentals (2nd Edition)

$\frac{dy}{dx} = \frac{1}{xlog_2(x)ln^2(2)}$
$y = log_2(log_2(x))$ Chain Rule: $\frac{dy}{dx} = \frac{1}{log_2(x)ln(2)} \times \frac{1}{xln(2)} = \frac{1}{xlog_2(x)ln^2(2)}$