Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.9 Derivatives of Logarithmic and Exponential Functions - 3.9 Exercises - Page 211: 60


$\frac{dy}{dx} = \frac{1}{xlog_2(x)ln^2(2)}$

Work Step by Step

$y = log_2(log_2(x))$ Chain Rule: $\frac{dy}{dx} = \frac{1}{log_2(x)ln(2)} \times \frac{1}{xln(2)} = \frac{1}{xlog_2(x)ln^2(2)}$
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