$s'(t) = -2^t\ln(2)\sin(2^t)$
Work Step by Step
If $f(x) = b^x$, then $f'(x) = b^xln(b)$ $s(t) = cos(2^t)$ Chain Rule: $s'(t) = 2^tln(2)(-sin(2^t)) = -2^t\ln(2)\sin(2^t)$
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