#### Answer

$s'(t) = -2^t\ln(2)\sin(2^t)$

#### Work Step by Step

If $f(x) = b^x$, then $f'(x) = b^xln(b)$
$s(t) = cos(2^t)$
Chain Rule:
$s'(t) = 2^tln(2)(-sin(2^t)) = -2^t\ln(2)\sin(2^t)$

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

$s'(t) = -2^t\ln(2)\sin(2^t)$

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