Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.7 The Chain Rule - 3.7 Exercises - Page 192: 75


$\frac{dy}{dx}= \frac{f'(x)}{2\sqrt {f(x)}}$

Work Step by Step

$y=\sqrt {f(x)} = (f(x))^{0.5}$ Chain Rule $\frac{dy}{dx} = 0.5(f(x))^{-0.5}(f'(x)) = \frac{f'(x)}{2\sqrt {f(x)}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.