Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.7 The Chain Rule - 3.7 Exercises: 75

Answer

$\frac{dy}{dx}= \frac{f'(x)}{2\sqrt {f(x)}}$

Work Step by Step

$y=\sqrt {f(x)} = (f(x))^{0.5}$ Chain Rule $\frac{dy}{dx} = 0.5(f(x))^{-0.5}(f'(x)) = \frac{f'(x)}{2\sqrt {f(x)}}$
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