## Calculus: Early Transcendentals (2nd Edition)

$\frac{dy}{dx}= \frac{f'(x)}{2\sqrt {f(x)}}$
$y=\sqrt {f(x)} = (f(x))^{0.5}$ Chain Rule $\frac{dy}{dx} = 0.5(f(x))^{-0.5}(f'(x)) = \frac{f'(x)}{2\sqrt {f(x)}}$