## Calculus: Early Transcendentals (2nd Edition)

$y'=e^{6x}(\cos x+6\sin x)$
$y=e^{6x}\sin x$ Start the differentiation process by applying the product rule: $y'=e^{6x}(\sin x)'+(e^{6x})'\sin x=...$ Evaluate the indicated derivatives and simplify: $...=e^{6x}\cos x+6e^{6x}\sin x=...$ Take out common factor $e^{6x}$: $...=e^{6x}(\cos x+6\sin x)$