Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.5 Derivatives of Trigonometric Functions - 3.5 Exercises - Page 169: 18

Answer

$y ' = 10x - sin (x)$

Work Step by Step

$y = 5x^2 + cos (x)$ $y' = (5x^2 + cos (x))' = (5x^2)' + (cos (x))'$ $(cos (x))' = - sin(x)$ $(5x^2)' = 2\times5x^1 = 10x$ Therefore $y' = (5x^2 + cos (x))' = (5x^2)' + (cos (x))' = 10x - sin (x)$
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