Answer
Not continuous
Work Step by Step
We are given the function:
$f(x)=\sqrt{x-2}$
We use the continuity checklist to determine if $f$ is continuous in $a=1$:
1) Determine the function's domain:
$x-2\geq 0$
$x\geq 2$
$D=[2,\infty)$
$a=1$ is not in the function's domain, therefore $f$ is not defined for $a=1$.
As the conditions 1 is not satisfied, the function is not continuous in $a=1$.
