Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 108: 14

Answer

Not continuous

Work Step by Step

We are given the function: $f(x)=\dfrac{2x^2+3x+1}{x^2+5x}$ We use the continuity checklist to determine if $f$ is continuous in $a=-5$: 1) $f(x)=\dfrac{2x^2+3x+1}{x^2+5x}=\dfrac{2x^2+2x+x+1}{x(x+5)}$ $=\dfrac{2x(x+1)+(x+1)}{x(x+5)}=\dfrac{(x+1)(2x+1)}{x(x+5)}$ $a=-5$ is a zero of the denominator, therefore $f$ is not defined for $a=5$. As the condition 1 from the continuity checklist is not satisfied, the function is not continuous in $a=-5$.
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