Answer
$x=0$
Work Step by Step
We are given the function:
$g(x)=2-\ln x^2$
Compute $\lim\limits_{x \to a} g(x)=\lim\limits_{x \to a} (2-\ln x^2)$
For $a=0$ we have:
$\lim\limits_{x \to 0^-} (2-\ln x^2)=\infty$
$\lim\limits_{x \to 0^+} (2-\ln x^2)=\infty$
Therefore $g(x)$ has a vertical asymptote in $x=0$.
