Answer
$\lim\limits_{t \to 5}\frac{4t^2-100}{t-5}=40 \\
$
Work Step by Step
$\lim\limits_{t \to 5}\frac{4t^2-100}{t-5}=\frac{4(25)-100}{5-5}=\frac{0}{0}\\
\lim\limits_{t \to 5}\frac{4t^2-100}{t-5}=\lim\limits_{t \to 5}\frac{4(t^2-25)}{t-5}=\\
\lim\limits_{t \to 5}\frac{4(t-5)(t+5)}{t-5}=\lim\limits_{t \to 5}4(t+5)=4(5+5)=40 \\
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