Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 14 - Vector Calculus - 14.5 Divergence and Curl - 14.5 Exercises - Page 1108: 33

Answer

0

Work Step by Step

curl $\textbf{F}=\nabla\times\textbf{F}=\nabla\times\langle z^{2}\sin y,xz^{2}\cos y,2xz\sin y\rangle$ $=(\frac{\partial (2xz\sin y)}{\partial y}-\frac{\partial (xz^{2}\cos y)}{\partial z})\textbf{i}+(\frac{\partial(z^{2}\sin y)}{\partial z}-\frac{\partial(2xz\sin y)}{\partial x})\textbf{j}+(\frac{\partial(xz^{2}\cos y)}{\partial x}-\frac{\partial(z^{2}\sin y)}{\partial y})\textbf{k}$ $=(2xz\cos y-2xz\cos y)\textbf{i}+(2z\sin y-2z\sin y)\textbf{j}+(z^{2}\cos y-z^{2}\cos y)\textbf{k}$ $=0$
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