Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 14 - Vector Calculus - 14.5 Divergence and Curl - 14.5 Exercises - Page 1108: 27

Answer

$3y\textbf{k}$

Work Step by Step

curl $\textbf{F}=\nabla\times\textbf{F}=\nabla\times\langle x^{2}-y^{2},xy,z\rangle$ $=(\frac{\partial (z)}{\partial y}-\frac{\partial (xy)}{\partial z})\textbf{i}+(\frac{\partial(x^{2}-y^{2})}{\partial z}-\frac{\partial(z)}{\partial x})\textbf{j}+(\frac{\partial(xy)}{\partial x}-\frac{\partial(x^{2}-y^{2})}{\partial y})\textbf{k}$ $=(0-0)\textbf{i}+(0-0)\textbf{j}+(y-(0-2y))\textbf{k}$ $=3y\textbf{k}$
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