Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 14 - Vector Calculus - 14.5 Divergence and Curl - 14.5 Exercises - Page 1107: 9

Answer

3

Work Step by Step

div $\textbf{F}$=$\nabla\cdot \textbf{F}=\nabla\cdot \langle2x,4y,-3z\rangle$ $=\frac{\partial}{\partial x}(2x)+\frac{\partial}{\partial y}(4y)+\frac{\partial}{\partial z}(-3z)$ $=2+4-3=3$
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