Answer
1
Work Step by Step
div $\textbf{F}=\nabla \cdot \textbf{F}=\nabla\cdot\langle-2y,3x,z\rangle$
$=\frac{\partial}{\partial x}(-2y)+\frac{\partial}{\partial y}(3x)+\frac{\partial}{\partial z}(z)$
$=0+0+1=1$
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