Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 13 - Multiple Integration - 13.4 Triple Integrals - 13.4 Exercises - Page 1002: 7

Answer

$$24$$

Work Step by Step

$$\eqalign{ & \int_{ - 2}^2 {\int_3^6 {\int_0^2 {dxdydz} } } \cr & {\text{Integrate with respect to }}x \cr & \int_{ - 2}^2 {\int_3^6 {\left[ x \right]_0^2dydz} } \cr & \int_{ - 2}^2 {\int_3^6 {\left( {2 - 0} \right)dydz} } \cr & \int_{ - 2}^2 {\int_3^6 {2dydz} } \cr & {\text{Integrate with respect to }}y \cr & \int_{ - 2}^2 {\left[ {2y} \right]_3^6dz} \cr & 2\int_{ - 2}^2 {\left( {6 - 3} \right)dz} \cr & 2\int_{ - 2}^2 {3dz} \cr & 6\int_{ - 2}^2 {dz} \cr & {\text{Integrate with respect to }}z \cr & 6\left[ z \right]_{ - 2}^2 \cr & = 6\left( {2 + 2} \right) \cr & = 24 \cr} $$
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