## Calculus: Early Transcendentals (2nd Edition)

Published by Pearson

# Chapter 11 - Vectors and Vector-Valued Functions - 11.2 Vectors in Three Dimensions - 11.2 Exercises - Page 778: 29

#### Answer

A sphere with radius $3$ centered at $(1,0,0)$

#### Work Step by Step

Equation of Sphere with Center $(a,b,c)$ and radius $r$ $(x-a)^2 + (y-b)^2 + (z-c)^2 = r^2$ Given Equation: $(x-1)^2 + y^2 + z^2 - 9 =0$ Rewritten: $(x-1)^2 + (y-0)^2 + (z-0)^2 =9$ $(x-1)^2 + (y-0)^2 + (z-0)^2 =3^2$ Center is at $(1,0,0)$ and radius is $3$.

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