Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.2 Vectors in Three Dimensions - 11.2 Exercises - Page 778: 11


A: $(3,-4,5)$ B: $(0,-4,0)$ C: $(0,-4,5)$

Work Step by Step

Given the two vertices, we find the peak value for each coordinate is $x=3$, $y=-4$, and $z=5$. A is directly on top of the vertex $(3,-4,0)$, meaning that only the $z$ coordinate is different. C is on the same plane as $(0,0,5)$, making the $z$ coordinate $10$. Thus, A is at $(3,-4,5)$. B is on the $yz$-plane and $xy$-plane, so the $x$ and $z$ coordinate is zero. Thus, B is at $(0,-4,0)$. C is on the $yz$-plane, so the $x$ coordinate is zero. Thus, C is at $(0,-4,5)$.
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