## Calculus: Early Transcendentals (2nd Edition)

$\log_{3}30=\dfrac{\ln30}{\ln3}\approx3.095903$
$\log_{3}30$ Apply the change of base formula, which is $\log_{b}x=\dfrac{\log_{a}x}{\log_{a}b}$, to express the given $\log$ in terms of the natural logarithm: $\log_{3}30=\dfrac{\ln30}{\ln3}$ Evaluate using a calculator: $\dfrac{\ln30}{\ln3}\approx3.095903$