Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises: 59


$\frac{\ln_{15}}{\ln_{2}} = 3.9069$

Work Step by Step

Change of base formula: $\log_{b}x = \frac{\log_{a}x}{\log_{a}b}$ $\log_{2}15 =\frac{\ln_{15}}{\ln_{2}} $ $\frac{\ln_{15}}{\ln_{2}} = 3.9069$
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