## Calculus: Early Transcendentals (2nd Edition)

Domain: $(0,\infty)$ Range: $(-\infty,\infty)$
Because the range of $b^{x}$ is $(0,\infty)$ the domain of $log_{b}x$ is $(0,\infty)$. The domain of $b^{x}$ is $(-\infty,\infty)$ which implies the range of $log_{b}x$ is $(-\infty,\infty)$.