Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 35: 10

Answer

$e^{5ln2}$

Work Step by Step

$2^{5} = e^{y}$ $ln2^{5} = lne^{y}$ $5ln2 = y$ $2^{5} = e^{5ln2}$
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