Calculus: Early Transcendentals (2nd Edition)

$(0,0)$ and $(4,16)$
$y=x^{2}$ $y=-x^{2}+8x$ $x^{2}=-x^{2}+8x$ $2x^{2}-8x=0$ $2x(x-4)=0$ $x=0,4$ $y(0)=(0)^{2}=0$ $y(4)=(4)^{2}=16$ $(0,0)$ and $(4,16)$