Answer
(2,6) and (-1,3)
Work Step by Step
$y=x^{2}+2$
$y=x+4$
$x^{2}+2=x+4$
$x^{2}-x-2=0$
$(x-2)(x+1)=0$
$x=2,-1$
$y=2+4=6$
$y=-1+4= 3$
(2,6) and (-1,3)
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.2 Representing Functions - 1.2 Exercises - Page 24: 56
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