## Calculus: Early Transcendentals (2nd Edition)

$f(g(2))=2$ $g(f(-2)=-2$
We know that $g(2)=-2$ and $f(2)=f(-2)$ (because f is even): $f(g(2)=f(-2))=f(2)=2$ $g(f(-2)=g(f(2))=g(2)=-2$