#### Answer

$\frac{1}{y^{6}+1}$

#### Work Step by Step

$f(x) = \frac{1}{x^{3}+1}$
Evaule $f(2)$
$f(2)= \frac{1}{2^{3}+1} = \frac{1}{9}$
Evaluate $f(y^{2})$
$f(y^{2})=\frac{1}{(y^{2})^{3}+1} = \frac{1}{y^{6}+1}$

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

$\frac{1}{y^{6}+1}$

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