Answer
$\frac{1}{y^{6}+1}$
Work Step by Step
$f(x) = \frac{1}{x^{3}+1}$
Evaule $f(2)$
$f(2)= \frac{1}{2^{3}+1} = \frac{1}{9}$
Evaluate $f(y^{2})$
$f(y^{2})=\frac{1}{(y^{2})^{3}+1} = \frac{1}{y^{6}+1}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 9: 4
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