## Calculus: Early Transcendentals (2nd Edition)

$f(x)=x^{5}-x^{3}-2$ $\textbf{Symmetry about the$x$-axis}$ This function has no symmetry about the x-axis, because if it had, it would violate the Vertical Rule Test. Another way to realize this is that changing $f(x)$ by $−f(x)$ does not yield an equivalent function. $\textbf{Symmetry about the$y$-axis}$ Substitute $x$ by $-x$ in $f(x)$ and simplify: $f(-x)=(-x)^{5}-(-x)^{3}-2=...$ $...=-x^{5}+x^{3}-2$ Since $f(-x)\ne f(x)$, the given function is not symmetric about the $y$-axis. $\textbf{Symmetry about the origin}$ It can be seen in the test for $y$-axis symmetry that $f(-x)\ne -f(x)$. Because of this, this function is not symmetric about the origin. The graph of this function is: