Answer
$\frac{f(x)-f(a)}{x-a}=(x+a)(x^2+a^2)$
Work Step by Step
$f(x) = x^4$
$\frac{f(x)-f(a)}{x-a}=\frac{x^4-a^4}{x-a} = \frac{(x^2-a^2)(x^2+a^2)}{(x-a)} =\frac{(x-a)(x+a)(x^2+a^2)}{(x-a)}=\frac{(x+a)(x^2+a^2)}{1}=(x+a)(x^2+a^2)$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 11: 62
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