Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 5 - Accumulating Change: Limits of Sums and the Definite Integral - 5.9 Activities - Page 409: 18


$\dfrac {x^{2}}{4}+\dfrac {1}{2}\ln x+c$

Work Step by Step

$$\int \dfrac {x^{2}+1}{2x}dx=\int \left( \dfrac {x^{2}}{2x}dx+\dfrac {1}{2x}dx\right) =\int \left( \dfrac {x}{2}+\dfrac {1}{2x}\right) dx=\dfrac {x^{2}}{4}+\dfrac {1}{2}\ln x+c$$
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