Answer
$x-\dfrac {1}{x}+c$
Work Step by Step
$$\int \dfrac {x^{2}+1}{x^{2}}dx=\int \left( 1+\dfrac {1}{x^{2}}\right) dx=\int \left( 1+x^{-2}\right) dx=x-x^{-1}+c=x-\dfrac {1}{x}+c$$
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 5 - Accumulating Change: Limits of Sums and the Definite Integral - 5.9 Activities - Page 409: 19
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