Answer
inside: $g(x)=6x^2+3^x$
outside: $f(g)=-12ln(g)$
derivative: $\frac{df}{dx}=\frac{-12}{6x^2+3^x}*(12x+3ln(x))$
Work Step by Step
Use the chain rule to take the derivative $\frac{d}{dx}f(g(x))=f'(g(x))g'(x)$
To find the inside, you take the number inside the parenthesis.
To find the outside, you exchange the parenthesis to a variable.
Then take its derivative and put it together.