Answer
inside: $g(x)=4x^3+1$
outside: $f(g)=7.2g^{-4}$
derivative: $f′(x)=28.8(4x^3+1)^{-5}∗12x^2$
Work Step by Step
Rewrite the function as $7.2(4x^3+1)^4$
Use the chain rule to take the derivative $\frac{d}{dx}f(g(x))=f′(g(x))g′(x)$
To find the inside, you take the number inside the parenthesis.
To find the outside, you exchange the parenthesis to a variable.
Then take its derivative and put it together.