Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.6 Inverse Trigonometric Functions - 6.6 Exercises - Page 481: 21

Answer

\[\frac{dy}{dx}=\frac{-1}{x\sqrt{x^2-1}}\]

Work Step by Step

Let \[y=\csc^{-1} x\] \[\Rightarrow x=\csc y\;\;\;...(1)\] Differentiate (1) implicitly with respect to $x$ \[-\csc y\cot y\frac{dy}{dx}=1\] \[\Rightarrow \frac{dy}{dx}=\frac{-1}{\csc y\cot y}\] \[\Rightarrow \frac{dy}{dx}=\frac{-1}{\csc y\sqrt{\csc^2-1}}\] Using (1) \[\Rightarrow \frac{dy}{dx}=\frac{-1}{x\sqrt{x^2-1}}\] Hence, \[\frac{dy}{dx}=\frac{-1}{x\sqrt{x^2-1}}\]
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