Answer
$tanx^{(secx)}=e^{secx ln(tanx)}$
Work Step by Step
As we know that $e^{lnx}=x$
Take exponent to the given term $tanx^{(secx)}$.
$tanx^{(secx)}=e^{ln (tanx)^{(secx)}}$
Since, $logx^{y}=xlogy$
Hence, $tanx^{(secx)}=e^{secx ln(tanx)}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.4* General Logarithmic and Exponential Functions - 6.4* Exercise - Page 463: 6
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