## Calculus 8th Edition

$tanx^{(secx)}=e^{secx ln(tanx)}$
As we know that $e^{lnx}=x$ Take exponent to the given term $tanx^{(secx)}$. $tanx^{(secx)}=e^{ln (tanx)^{(secx)}}$ Since, $logx^{y}=xlogy$ Hence, $tanx^{(secx)}=e^{secx ln(tanx)}$