Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4 Derivatives of Logarithmic Functions - 6.4 Exercises - Page 438: 86

Answer

$\pi\ln(10)$

Work Step by Step

$$V=\int_0^3 2\pi x \frac{1}{x^2+1}dx$$ $$V=\pi\int_0^3 \frac{2x}{x^2+1}dx$$ $$V=\pi\int_0^3 \frac{(x^2+1)'}{x^2+1}dx$$ $$V=\pi[\ln(x^2+1)]_0^3=\pi\ln(3^2+1)-\pi\ln(0^2+1)=\pi\ln(10)$$
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