Answer
$\int \frac{cos(lnt)}{t}dt=sin(lnt)+Constant$
Work Step by Step
Evaluate $\int \frac{cos(lnt)}{t}dt$.
Consider $ln t =u$ and $\frac{1}{t} dt = du$
Thus, $\int \frac{cos(lnt)}{t}dt=\int cos (u) du$
$=sin(u)+ Constant$
$=sin(lnt)+Constant$
Hence, $\int \frac{cos(lnt)}{t}dt=sin(lnt)+Constant$
